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15m^2+31m+10=0
a = 15; b = 31; c = +10;
Δ = b2-4ac
Δ = 312-4·15·10
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-19}{2*15}=\frac{-50}{30} =-1+2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+19}{2*15}=\frac{-12}{30} =-2/5 $
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